Step of Proof: ax_choice |
12,41 |
|
Inference at * 1 1 1 1
Iof proof for Lemma ax choice:
1. A : Type
2. B : Type
3. Q : A
B

4. g : x:A
y:B
Q(x,y)
5. x : A
6. y : y:B
Q(x,y)
7. y = g(x)
Q(x,(g(x)).1)
by D 6
1:
1: 6. y1 : B
1: 7. y2 : Q(x,y1)
1: 8. <y1, y2> = g(x)
1:
Q(x,(g(x)).1)
.